What are the solutions to the equation 2x^2+x+1=64+40+2 ?

The solutions to the equation 2x^2+x+1=64+40+2 are x=7,x=-15/2

Find the zeros of 2x^2+x+1=64+40+2

The zeros of 2x^2+x+1=64+40+2 are x=7,x=-15/2

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2 x^{2} + x + 1 = 64 + 40 + 2

x = 7, x = - \frac{15}{2}

Decimal Notation

x = 7, x = - 7.5

Solution steps

2 x^{2} + x + 1 = 64 + 40 + 2

Refine

2 x^{2} + x + 1 = 106

Move

106

to the left side

2 x^{2} + x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 105 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 105) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 2}, x_{2} = \frac{- 1 - 29}{2 \cdot 2}

x = \frac{- 1 + 29}{2 \cdot 2} : 7

x = \frac{- 1 - 29}{2 \cdot 2} : - \frac{15}{2}

The solutions to the quadratic equation are:

x = 7, x = - \frac{15}{2}

\frac{π}{\frac{1}{4}}

- 4 x^{2} = - 13 x + 15

6 x^{2} + 27 x + 12

(x + 4 i) (x - 4 i)

7 x + 11 x = 144

What are the solutions to the equation 2x^2+x+1=64+40+2 ?
The solutions to the equation 2x^2+x+1=64+40+2 are x=7,x=-15/2
Find the zeros of 2x^2+x+1=64+40+2
The zeros of 2x^2+x+1=64+40+2 are x=7,x=-15/2