What are the solutions to the equation -x^2+5x-8=0 ?

The solutions to the equation -x^2+5x-8=0 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2

Find the zeros of -x^2+5x-8=0

The zeros of -x^2+5x-8=0 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2

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- x^{2} + 5 x - 8 = 0

x = \frac{5}{2} - i \frac{7}{2}, x = \frac{5}{2} + i \frac{7}{2}

Solution steps

- x^{2} + 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

5^{2} - 4 (- 1) (- 8) : 7 i

x_{1, 2} = \frac{- 5 \pm 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 7 i}{2 ( - 1 )}, x_{2} = \frac{- 5 - 7 i}{2 ( - 1 )}

x = \frac{- 5 + 7 i}{2 ( - 1 )} : \frac{5}{2} - i \frac{7}{2}

x = \frac{- 5 - 7 i}{2 ( - 1 )} : \frac{5}{2} + i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} - i \frac{7}{2}, x = \frac{5}{2} + i \frac{7}{2}

\frac{y ^{- 2} y ^{6}}{x ^{- 7} x ^{6}}

\frac{2 x + 2}{4} \geq 2

2 4^{\frac{1}{3}}

6 x - 2 = - 20

- 2 v^{2} - v + 21

What are the solutions to the equation -x^2+5x-8=0 ?
The solutions to the equation -x^2+5x-8=0 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2
Find the zeros of -x^2+5x-8=0
The zeros of -x^2+5x-8=0 are x= 5/2-i(sqrt(7))/2 ,x= 5/2+i(sqrt(7))/2