|k+6|=3

Lösung

∣ k + 6 ∣ = 3

k = - 9 or k = - 3

Schritte zur Lösung

∣ k + 6 ∣ = 3

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

k + 6 = - 3 or k + 6 = 3

k + 6 = - 3 or k + 6 = 3

k = - 9 or k = - 3

3 x + x^{2} = 8

14 + 9 + x \leq 4

3 x^{2} - 24 x + 46 = 0

x^{2} + 1 \geq 0

\frac{5 - 2 x}{6} \leq \frac{1}{4} - \frac{3 x}{2}