What are the solutions to the equation x^2-4x-13=0 ?

The solutions to the equation x^2-4x-13=0 are x=2+sqrt(17),x=2-sqrt(17)

Find the zeros of x^2-4x-13=0

The zeros of x^2-4x-13=0 are x=2+sqrt(17),x=2-sqrt(17)

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x^{2} - 4 x - 13 = 0

x = 2 + 17, x = 2 - 17

Decimal Notation

x = 6.12310 \dots, x = - 2.12310 \dots

Solution steps

x^{2} - 4 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 13 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 13) = 217

x_{1, 2} = \frac{- ( - 4 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 17}{2 \cdot 1} : 2 + 17

x = \frac{- ( - 4 ) - 2 17}{2 \cdot 1} : 2 - 17

The solutions to the quadratic equation are:

x = 2 + 17, x = 2 - 17

25 x^{2} + 30 x + 10

2 x^{2} + 6 x

7 z^{2} - 8 z - 21 = 0

in t (x 9 - x^{2}) d x

lo g_{9} (\frac{1}{27})

What are the solutions to the equation x^2-4x-13=0 ?
The solutions to the equation x^2-4x-13=0 are x=2+sqrt(17),x=2-sqrt(17)
Find the zeros of x^2-4x-13=0
The zeros of x^2-4x-13=0 are x=2+sqrt(17),x=2-sqrt(17)