What is the answer to (x-1)/3+(2x+1)/5 =(3x-1)/4 ?

The answer to (x-1)/3+(2x+1)/5 =(3x-1)/4 is x=7

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(x-1)/3+(2x+1)/5 =(3x-1)/4

\frac{x - 1}{3} + \frac{2 x + 1}{5} = \frac{3 x - 1}{4}

x = 7

Solution steps

\frac{x - 1}{3} + \frac{2 x + 1}{5} = \frac{3 x - 1}{4}

Multiply by LCM

20 (x - 1) + 12 (2 x + 1) = 15 (3 x - 1)

Expand

20 (x - 1) + 12 (2 x + 1) : 44 x - 8

Expand

15 (3 x - 1) : 45 x - 15

44 x - 8 = 45 x - 15

Move

8

to the right side

44 x = 45 x - 7

Move

45 x

to the left side

- x = - 7

Divide both sides by

- 1

x = 7

4 x^{2} + 4 = 0

\frac{x - 6}{x + 2} \geq 0

(x - y)^{2} + 4 (x - y) + 3

∣ 8 x + 4 ∣ < 28

\frac{a + 1}{a ^{2} - a} - \frac{a + 2}{2 a ^{2} - 2}

What is the answer to (x-1)/3+(2x+1)/5 =(3x-1)/4 ?
The answer to (x-1)/3+(2x+1)/5 =(3x-1)/4 is x=7
Solve for x: (x-1)/3+(2x+1)/5 =(3x-1)/4
The solution is x=7