What are the solutions to the equation 69x^2+2x-12=0 ?

The solutions to the equation 69x^2+2x-12=0 are x=(-1+sqrt(829))/(69),x=-(1+sqrt(829))/(69)

Find the zeros of 69x^2+2x-12=0

The zeros of 69x^2+2x-12=0 are x=(-1+sqrt(829))/(69),x=-(1+sqrt(829))/(69)

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69 x^{2} + 2 x - 12 = 0

x = \frac{- 1 + 829}{69}, x = - \frac{1 + 829}{69}

Decimal Notation

x = 0.40278 \dots, x = - 0.43177 \dots

Solution steps

69 x^{2} + 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 69 ( - 12 )}{2 \cdot 69}

2^{2} - 4 \cdot 69 (- 12) = 2829

x_{1, 2} = \frac{- 2 \pm 2 829}{2 \cdot 69}

Separate the solutions

x_{1} = \frac{- 2 + 2 829}{2 \cdot 69}, x_{2} = \frac{- 2 - 2 829}{2 \cdot 69}

x = \frac{- 2 + 2 829}{2 \cdot 69} : \frac{- 1 + 829}{69}

x = \frac{- 2 - 2 829}{2 \cdot 69} : - \frac{1 + 829}{69}

The solutions to the quadratic equation are:

x = \frac{- 1 + 829}{69}, x = - \frac{1 + 829}{69}

\frac{3 x - 12}{5} = 6

x + 4 = 7

36 s^{2} - 60 s + 25

x^{3} - 4 x^{2} \leq - x + 4

\frac{1}{2} x + 8 < 10

What are the solutions to the equation 69x^2+2x-12=0 ?
The solutions to the equation 69x^2+2x-12=0 are x=(-1+sqrt(829))/(69),x=-(1+sqrt(829))/(69)
Find the zeros of 69x^2+2x-12=0
The zeros of 69x^2+2x-12=0 are x=(-1+sqrt(829))/(69),x=-(1+sqrt(829))/(69)