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受欢迎的代数 >

7=(4(1)^3)/9+(2x(1)^{3/2})/3+(x^2)/4

解答

7 = \frac{4 ( 1 ) ^{3}}{9} + \frac{2 x ( 1 ) ^{\frac{3}{2}}}{3} + \frac{x ^{2}}{4}

解答

x = \frac{2 ( 3 \cdot 7 ^{\frac{1}{2}} - 2 )}{3}, x = - \frac{2 ( 2 + 3 \cdot 7 ^{\frac{1}{2}} )}{3}

+1

十进制

x = 3.95816 \dots, x = - 6.62483 \dots

求解步骤

7 = \frac{4 ( 1 ) ^{3}}{9} + \frac{2 x ( 1 ) ^{\frac{3}{2}}}{3} + \frac{x ^{2}}{4}

找到

9, 3, 4

的最小公倍数:

36

乘以最小公倍数=

36

7 \cdot 36 = \frac{4 \cdot 1 ^{3}}{9} \cdot 36 + \frac{2 x \cdot 1 ^{\frac{3}{2}}}{3} \cdot 36 + \frac{x ^{2}}{4} \cdot 36

化简

252 = 16 + 24 x + 9 x^{2}

交换两边

16 + 24 x + 9 x^{2} = 252

将

252

para o lado esquerdo

9 x^{2} + 24 x - 236 = 0

使用求根公式求解

x_{1, 2} = \frac{- 24 \pm ( 2 4 ^{2} - 4 \cdot 9 ( - 236 ) ) ^{\frac{1}{2}}}{2 \cdot 9}

(2 4^{2} - 4 \cdot 9 (- 236))^{\frac{1}{2}} = 36 \cdot 7^{\frac{1}{2}}

x_{1, 2} = \frac{- 24 \pm 36 \cdot 7 ^{\frac{1}{2}}}{2 \cdot 9}

将解分隔开

x_{1} = \frac{- 24 + 36 \cdot 7 ^{\frac{1}{2}}}{2 \cdot 9}, x_{2} = \frac{- 24 - 36 \cdot 7 ^{\frac{1}{2}}}{2 \cdot 9}

x = \frac{- 24 + 36 \cdot 7 ^{\frac{1}{2}}}{2 \cdot 9} : \frac{2 ( 3 \cdot 7 ^{\frac{1}{2}} - 2 )}{3}

x = \frac{- 24 - 36 \cdot 7 ^{\frac{1}{2}}}{2 \cdot 9} : - \frac{2 ( 2 + 3 \cdot 7 ^{\frac{1}{2}} )}{3}

二次方程组的解是:

x = \frac{2 ( 3 \cdot 7 ^{\frac{1}{2}} - 2 )}{3}, x = - \frac{2 ( 2 + 3 \cdot 7 ^{\frac{1}{2}} )}{3}

作图

流行的例子

0 = 200 \cdot 2 \cdot 2 - 2 \cdot x

3 x - 5 x + 8 x + x = 42

87=(1/2)(pi/4)r^2

87 = (\frac{1}{2}) (\frac{π}{4}) r^{2}

∣ 3 - 8 x ∣ \geq 5

化简 2/5-1/4 (1/4)^2+1/2

s im pl i f y \frac{2}{5} - \frac{1}{4} (\frac{1}{4})^{2} + \frac{1}{2}