What is (3b^2+18b)/(b+6)*1/(b+8) ?

The solution to (3b^2+18b)/(b+6)*1/(b+8) is (3b)/(b+8)

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simplify (3b^2+18b)/(b+6)*1/(b+8)

simplify

\frac{3 b ^{2} + 18 b}{b + 6} \cdot \frac{1}{b + 8}

\frac{3 b}{b + 8}

Solution steps

\frac{3 b ^{2} + 18 b}{b + 6} \cdot \frac{1}{b + 8}

Cancel

\frac{3 b ^{2} + 18 b}{b + 6} : 3 b

= 3 b \frac{1}{b + 8}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 b \cdot 1}{b + 8}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3 b}{b + 8}

4 (3 x + 1) = 40 + 3 x

\frac{t}{60} \cdot 75 = 60 \cdot \frac{( t + 14 )}{60}

(1 + \frac{0.045}{12})^{12} - 1

3 - ∣ 3 w + 9 ∣ = 6

(\frac{h}{g})^{2}

What is (3b^2+18b)/(b+6)*1/(b+8) ?
The solution to (3b^2+18b)/(b+6)*1/(b+8) is (3b)/(b+8)