What is factor 4x^{(3)}+8x^{(2)}-x-2 ?

The solution to factor 4x^{(3)}+8x^{(2)}-x-2 is (x+2)(2x+1)(2x-1)

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factor 4x^{(3)}+8x^{(2)}-x-2

factor

4 x^{(3)} + 8 x^{(2)} - x - 2

(x + 2) (2 x + 1) (2 x - 1)

Solution steps

4 x^{3} + 8 x^{2} - x - 2

= (4 x^{3} + 8 x^{2}) + (- x - 2)

Factor out

4 x^{2}

from

4 x^{3} + 8 x^{2} : 4 x^{2} (x + 2)

Factor out

- 1

from

- x - 2 : - (x + 2)

= 4 x^{2} (x + 2) - (x + 2)

Factor out common term

(x + 2) : (x + 2) (4 x^{2} - 1)

= (x + 2) (4 x^{2} - 1)

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= (x + 2) (2 x + 1) (2 x - 1)

4 (a + b)^{2} + 11 (a + b) - 3

- \frac{\frac{16}{49}}{( - \frac{4}{35} )}

7.5

2 x^{2} + 9 x - 5 = 0

20 - 15 t^{2} \geq 0

What is factor 4x^{(3)}+8x^{(2)}-x-2 ?
The solution to factor 4x^{(3)}+8x^{(2)}-x-2 is (x+2)(2x+1)(2x-1)