What are the solutions to the equation 3x^2-12x-34=2 ?

The solutions to the equation 3x^2-12x-34=2 are x=6,x=-2

Find the zeros of 3x^2-12x-34=2

The zeros of 3x^2-12x-34=2 are x=6,x=-2

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3 x^{2} - 12 x - 34 = 2

x = 6, x = - 2

Solution steps

3 x^{2} - 12 x - 34 = 2

Move

2

to the left side

3 x^{2} - 12 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 36 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 36) = 24

x_{1, 2} = \frac{- ( - 12 ) \pm 24}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 24}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 24}{2 \cdot 3}

x = \frac{- ( - 12 ) + 24}{2 \cdot 3} : 6

x = \frac{- ( - 12 ) - 24}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 6, x = - 2

4 x^{2} - x - 1 = 0

x^{2} - 14 = 2 x - 14

\frac{6 x ^{8} y ^{9}}{5 x ^{2} y ^{4}}

s^{2} + 3 s + 2 < 0

2 = x + \frac{2}{3}

What are the solutions to the equation 3x^2-12x-34=2 ?
The solutions to the equation 3x^2-12x-34=2 are x=6,x=-2
Find the zeros of 3x^2-12x-34=2
The zeros of 3x^2-12x-34=2 are x=6,x=-2