What are the solutions to the equation -x^2+2x-8=0 ?

The solutions to the equation -x^2+2x-8=0 are x=1-sqrt(7)i,x=1+sqrt(7)i

Find the zeros of -x^2+2x-8=0

The zeros of -x^2+2x-8=0 are x=1-sqrt(7)i,x=1+sqrt(7)i

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- x^{2} + 2 x - 8 = 0

x = 1 - 7 i, x = 1 + 7 i

Solution steps

- x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 8) : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 7 i}{2 ( - 1 )}

x = \frac{- 2 + 2 7 i}{2 ( - 1 )} : 1 - 7 i

x = \frac{- 2 - 2 7 i}{2 ( - 1 )} : 1 + 7 i

The solutions to the quadratic equation are:

x = 1 - 7 i, x = 1 + 7 i

2 x^{2} - x - 2 = 0

∣ 5 x + 1 ∣ + 3 = 10

- 6 (w + 1) = 2 (1 - 3 w) - 8

25 x^{2} = 49

8 + 8 i

What are the solutions to the equation -x^2+2x-8=0 ?
The solutions to the equation -x^2+2x-8=0 are x=1-sqrt(7)i,x=1+sqrt(7)i
Find the zeros of -x^2+2x-8=0
The zeros of -x^2+2x-8=0 are x=1-sqrt(7)i,x=1+sqrt(7)i