What are the solutions to the equation 8=x^2-8x-15 ?

The solutions to the equation 8=x^2-8x-15 are x=4+sqrt(39),x=4-sqrt(39)

Find the zeros of 8=x^2-8x-15

The zeros of 8=x^2-8x-15 are x=4+sqrt(39),x=4-sqrt(39)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 = x^{2} - 8 x - 15

x = 4 + 39, x = 4 - 39

Decimal Notation

x = 10.24499 \dots, x = - 2.24499 \dots

Solution steps

8 = x^{2} - 8 x - 15

Switch sides

x^{2} - 8 x - 15 = 8

Move

8

to the left side

x^{2} - 8 x - 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 23 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 23) = 239

x_{1, 2} = \frac{- ( - 8 ) \pm 2 39}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 39}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 39}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 39}{2 \cdot 1} : 4 + 39

x = \frac{- ( - 8 ) - 2 39}{2 \cdot 1} : 4 - 39

The solutions to the quadratic equation are:

x = 4 + 39, x = 4 - 39

- 16 t^{2} + 50 t = 0

4 x^{2} - 200 = - 20

2 y^{2} + 10 y = - 7

(x - 1) (x - 2) (x - 6) > 0

9 x^{2} - 9 x + 2

What are the solutions to the equation 8=x^2-8x-15 ?
The solutions to the equation 8=x^2-8x-15 are x=4+sqrt(39),x=4-sqrt(39)
Find the zeros of 8=x^2-8x-15
The zeros of 8=x^2-8x-15 are x=4+sqrt(39),x=4-sqrt(39)