What are the solutions to the equation x^2-2x=1 ?

The solutions to the equation x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of x^2-2x=1

The zeros of x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)

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x^{2} - 2 x = 1

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

x^{2} - 2 x = 1

Move

1

to the left side

x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

x = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

3 (x - 1) - 5 x \geq x + 3

(4 x^{\frac{5}{4}}) (2 x^{\frac{1}{2}})

2 (x - 4)^{2} + 6 = 30

e^{- \frac{2}{3}}

lo g_{64} (\frac{1}{4})

What are the solutions to the equation x^2-2x=1 ?
The solutions to the equation x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of x^2-2x=1
The zeros of x^2-2x=1 are x=1+sqrt(2),x=1-sqrt(2)