4x^2-x-14<= 0

Lösung

4 x^{2} - x - 14 \leq 0

- \frac{7}{4} \leq x \leq 2

Intervall-Notation

[- \frac{7}{4}, 2]

Dezimale

- 1.75 \leq x \leq 2

Schritte zur Lösung

4 x^{2} - x - 14 \leq 0

Faktorisiere

4 x^{2} - x - 14 : (4 x + 7) (x - 2)

(4 x + 7) (x - 2) \leq 0

Identifiziere die Intervalle

- \frac{7}{4} \leq x \leq 2

3 x + 3 = 3

9 t^{2} - 12 t + 4 = 0

4 (a - 2) = 3 (a + 4)

3 (x - 2) = 2 x - 4

∣ 8 x - 5 ∣ \leq 6