What is factor 25x^2-20x+4 ?

The solution to factor 25x^2-20x+4 is (5x-2)^2

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factor 25x^2-20x+4

factor

25 x^{2} - 20 x + 4

(5 x - 2)^{2}

Solution steps

25 x^{2} - 20 x + 4

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 x^{2} = (5 x)^{2}

4 = 2^{2}

- 20 x = - 2 \cdot 5 x \cdot 2

= (5 x)^{2} - 2 \cdot 5 x \cdot 2 + 2^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(5 x)^{2} - 2 \cdot 5 x \cdot 2 + 2^{2} = (5 x - 2)^{2}

= (5 x - 2)^{2}

(x^{3} y^{6})^{- 2} + (x^{2} y^{4})^{- 3}

- 4.9 x^{2} + 19.6 x + 58.8 = 0

\frac{x ^{2} - 25}{x - 1} \leq 0

- 6 q - 1 \geq 10 q - 2

6 r^{2} - 10 r - 24