What is the answer to |6y+2|=2|2y-1| ?

The answer to |6y+2|=2|2y-1| is y=-2\lor y=0

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|6y+2|=2|2y-1|

∣ 6 y + 2 ∣ = 2 ∣ 2 y - 1 ∣

y = - 2 or y = 0

Solution steps

∣ 6 y + 2 ∣ = 2 ∣ 2 y - 1 ∣

Find positive and negative intervals

y < - \frac{1}{3}, - \frac{1}{3} \leq y < \frac{1}{2}, y \geq \frac{1}{2}

Solve the inequality for each interval

y = - 2 or y = 0 or No Solution

y = - 2 or y = 0

f = 9 (3)^{- 4}

2 x^{2} - 4 = - 204

(1 - 3)^{2}

∣ 5 - x ∣ = \frac{1}{5}

8 - m^{3}

What is the answer to |6y+2|=2|2y-1| ?
The answer to |6y+2|=2|2y-1| is y=-2\lor y=0
Solve for y: |6y+2|=2|2y-1|
The solution is y=-2\lor y=0