What is the answer to |x^2+x|=7 ?

The answer to |x^2+x|=7 is x=(-1-sqrt(29))/2 \lor x=(-1+sqrt(29))/2

Solve for x: |x^2+x|=7

The solution is x=(-1-sqrt(29))/2 \lor x=(-1+sqrt(29))/2

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x^{2} + x = 7

x = \frac{- 1 - 29}{2} or x = \frac{- 1 + 29}{2}

Decimal Notation

x = - 3.19258 \dots, x = 2.19258 \dots

Solution steps

x^{2} + x = 7

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + x = - 7 or x^{2} + x = 7

x^{2} + x = - 7 or x^{2} + x = 7

No Solution or (x = \frac{- 1 - 29}{2} or x = \frac{- 1 + 29}{2})

x = \frac{- 1 - 29}{2} or x = \frac{- 1 + 29}{2}

\frac{( 2 x + 7 )}{3} - \frac{( 3 x - 6 )}{4} - \frac{( x + 3 )}{2} = \frac{( 4 x + 9 )}{6}

- 2 < 3 x - 2 \leq 7

∣ x ∣ - 7 = 8

2.5 (\frac{π}{6})

4 (d + 3) - 3 (d - 2) = 1.2

What is the answer to |x^2+x|=7 ?
The answer to |x^2+x|=7 is x=(-1-sqrt(29))/2 \lor x=(-1+sqrt(29))/2
Solve for x: |x^2+x|=7
The solution is x=(-1-sqrt(29))/2 \lor x=(-1+sqrt(29))/2