What are the solutions to the equation 2x^2-x+1=0 ?

The solutions to the equation 2x^2-x+1=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4

Find the zeros of 2x^2-x+1=0

The zeros of 2x^2-x+1=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4

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2 x^{2} - x + 1 = 0

x = \frac{1}{4} + i \frac{7}{4}, x = \frac{1}{4} - i \frac{7}{4}

Solution steps

2 x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 1 : 7 i

x_{1, 2} = \frac{- ( - 1 ) \pm 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7 i}{2 \cdot 2} : \frac{1}{4} + i \frac{7}{4}

x = \frac{- ( - 1 ) - 7 i}{2 \cdot 2} : \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{7}{4}, x = \frac{1}{4} - i \frac{7}{4}

(2 + 3 i) (2 - 3 i)

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125 n^{3} + 216

8 x - 16

5 x^{2} - 34 x - 7

What are the solutions to the equation 2x^2-x+1=0 ?
The solutions to the equation 2x^2-x+1=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4
Find the zeros of 2x^2-x+1=0
The zeros of 2x^2-x+1=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4