What is (19n^3+38n^2)/(-57n^3+38n^2) ?

The solution to (19n^3+38n^2)/(-57n^3+38n^2) is (n+2)/(-3n+2)

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simplify (19n^3+38n^2)/(-57n^3+38n^2)

simplify

\frac{19 n ^{3} + 38 n ^{2}}{- 57 n ^{3} + 38 n ^{2}}

\frac{n + 2}{- 3 n + 2}

Solution steps

\frac{19 n ^{3} + 38 n ^{2}}{- 57 n ^{3} + 38 n ^{2}}

Factor

19 n^{3} + 38 n^{2} : 19 n^{2} (n + 2)

= \frac{19 n ^{2} ( n + 2 )}{- 57 n ^{3} + 38 n ^{2}}

Factor

- 57 n^{3} + 38 n^{2} : 19 n^{2} (- 3 n + 2)

= \frac{19 n ^{2} ( n + 2 )}{19 n ^{2} ( - 3 n + 2 )}

Cancel the common factor:

19

= \frac{n ^{2} ( n + 2 )}{n ^{2} ( - 3 n + 2 )}

Cancel the common factor:

n^{2}

= \frac{n + 2}{- 3 n + 2}

\frac{1}{4} n^{2} + \frac{3}{2} n = - \frac{3}{4}

- 2 x^{2} + 6 x - 4 = 0

x^{2} + 12 x y + 35 y^{2}

4 v^{3} - 12 v^{2} - 5 v + 15

- ln (3 + 32)

What is (19n^3+38n^2)/(-57n^3+38n^2) ?
The solution to (19n^3+38n^2)/(-57n^3+38n^2) is (n+2)/(-3n+2)