What is the answer to |x^2-2x+1|=2 ?

The answer to |x^2-2x+1|=2 is x=1-sqrt(2)\lor x=1+sqrt(2)

Solve for x: |x^2-2x+1|=2

The solution is x=1-sqrt(2)\lor x=1+sqrt(2)

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x^{2} - 2 x + 1 = 2

x = 1 - 2 or x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 2.41421 \dots

Solution steps

x^{2} - 2 x + 1 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x + 1 = - 2 or x^{2} - 2 x + 1 = 2

x^{2} - 2 x + 1 = - 2 or x^{2} - 2 x + 1 = 2

No Solution or (x = 1 - 2 or x = 1 + 2)

x = 1 - 2 or x = 1 + 2

\frac{1 + 2 i}{3 - 4 i} + \frac{2 - i}{5 i}

f = 10 (60 - 65) + 50

26 = 6 x - 4

(x + 1)^{2} = 3 x + 7

(x - 2) (x + 4) = 7

What is the answer to |x^2-2x+1|=2 ?
The answer to |x^2-2x+1|=2 is x=1-sqrt(2)\lor x=1+sqrt(2)
Solve for x: |x^2-2x+1|=2
The solution is x=1-sqrt(2)\lor x=1+sqrt(2)