What are the solutions to the equation 2x-x^2+1=0 ?

The solutions to the equation 2x-x^2+1=0 are x=1-sqrt(2),x=1+sqrt(2)

Find the zeros of 2x-x^2+1=0

The zeros of 2x-x^2+1=0 are x=1-sqrt(2),x=1+sqrt(2)

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2 x - x^{2} + 1 = 0

x = 1 - 2, x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 2.41421 \dots

Solution steps

2 x - x^{2} + 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 1 = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 2}{2 ( - 1 )}

x = \frac{- 2 + 2 2}{2 ( - 1 )} : 1 - 2

x = \frac{- 2 - 2 2}{2 ( - 1 )} : 1 + 2

The solutions to the quadratic equation are:

x = 1 - 2, x = 1 + 2

- \frac{( 3 x - 1 )}{3} - \frac{2 ( x - 8 )}{5} = \frac{( x + 8 )}{5} - 3

4 x^{4} - y^{2}

- 5 x^{2} - 30 x + 80

lo g_{7} (\frac{3}{16})

\frac{1}{2} \cdot 15 \cdot 12

What are the solutions to the equation 2x-x^2+1=0 ?
The solutions to the equation 2x-x^2+1=0 are x=1-sqrt(2),x=1+sqrt(2)
Find the zeros of 2x-x^2+1=0
The zeros of 2x-x^2+1=0 are x=1-sqrt(2),x=1+sqrt(2)