What is factor b^2-9b+8 ?

The solution to factor b^2-9b+8 is (b-1)(b-8)

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factor b^2-9b+8

factor

b^{2} - 9 b + 8

(b - 1) (b - 8)

Solution steps

b^{2} - 9 b + 8

Break the expression into groups

= (b^{2} - b) + (- 8 b + 8)

Factor out

b

from

b^{2} - b : b (b - 1)

Factor out

- 8

from

- 8 b + 8 : - 8 (b - 1)

= b (b - 1) - 8 (b - 1)

Factor out common term

b - 1

= (b - 1) (b - 8)

lo g_{4} (256) = x

4 t^{3} + 3 t^{2} + 2 t

- 5 = 9 a^{2} + 46 a

4 x^{2} + 5 x = 6

\frac{x}{3} = - 10