x^2+12x+32=0

解

x^{2} + 12 x + 32 = 0

x = - 4, x = - 8

解答ステップ

x^{2} + 12 x + 32 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 32 = 4

x_{1, 2} = \frac{- 12 \pm 4}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 12 + 4}{2 \cdot 1}, x_{2} = \frac{- 12 - 4}{2 \cdot 1}

x = \frac{- 12 + 4}{2 \cdot 1} : - 4

x = \frac{- 12 - 4}{2 \cdot 1} : - 8

二次equationの解:

x = - 4, x = - 8