What are the solutions to the equation y^2+8y-2=0 ?

The solutions to the equation y^2+8y-2=0 are y=-4+3sqrt(2),y=-4-3sqrt(2)

Find the zeros of y^2+8y-2=0

The zeros of y^2+8y-2=0 are y=-4+3sqrt(2),y=-4-3sqrt(2)

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y^{2} + 8 y - 2 = 0

y = - 4 + 32, y = - 4 - 32

Decimal Notation

y = 0.24264 \dots, y = - 8.24264 \dots

Solution steps

y^{2} + 8 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 2) = 62

y_{1, 2} = \frac{- 8 \pm 6 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 6 2}{2 \cdot 1}, y_{2} = \frac{- 8 - 6 2}{2 \cdot 1}

y = \frac{- 8 + 6 2}{2 \cdot 1} : - 4 + 32

y = \frac{- 8 - 6 2}{2 \cdot 1} : - 4 - 32

The solutions to the quadratic equation are:

y = - 4 + 32, y = - 4 - 32

13 x^{2} - 38 x - 3

3 0^{\circ} \cdot \frac{π}{18 0 ^{\circ}}

4 x^{2} + 36 x + 81 = 0

2 x^{2} + 16 < 8 x

8 w^{2} - 18 w + 9

What are the solutions to the equation y^2+8y-2=0 ?
The solutions to the equation y^2+8y-2=0 are y=-4+3sqrt(2),y=-4-3sqrt(2)
Find the zeros of y^2+8y-2=0
The zeros of y^2+8y-2=0 are y=-4+3sqrt(2),y=-4-3sqrt(2)