What are the solutions to the equation x+(x*0.1x)=75 ?

The solutions to the equation x+(x*0.1x)=75 are x=(-1+sqrt(31))/(0.2),x=(-1-sqrt(31))/(0.2)

Find the zeros of x+(x*0.1x)=75

The zeros of x+(x*0.1x)=75 are x=(-1+sqrt(31))/(0.2),x=(-1-sqrt(31))/(0.2)

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x + (x \cdot 0.1 x) = 75

x = \frac{- 1 + 31}{0.2}, x = \frac{- 1 - 31}{0.2}

Decimal Notation

x = 22.83882 \dots, x = - 32.83882 \dots

Solution steps

x + (x \cdot 0.1 x) = 75

Expand

x + (x \cdot 0.1 x) : x + 0.1 x^{2}

x + 0.1 x^{2} = 75

Move

75

to the left side

x + 0.1 x^{2} - 75 = 0

Write in the standard form

a x^{2} + b x + c = 0

0.1 x^{2} + x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 0.1 ( - 75 )}{2 \cdot 0.1}

1^{2} - 4 \cdot 0.1 (- 75) = 31

x_{1, 2} = \frac{- 1 \pm 31}{2 \cdot 0.1}

Separate the solutions

x_{1} = \frac{- 1 + 31}{2 \cdot 0.1}, x_{2} = \frac{- 1 - 31}{2 \cdot 0.1}

x = \frac{- 1 + 31}{2 \cdot 0.1} : \frac{- 1 + 31}{0.2}

x = \frac{- 1 - 31}{2 \cdot 0.1} : \frac{- 1 - 31}{0.2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 31}{0.2}, x = \frac{- 1 - 31}{0.2}

5 w + 18 \geq 8 w + 2 - 3 w

e^{x} e^{- x}

72 x - 2 x^{7}

s^{2} + 3 s + 16 = 0

x^{2} + 2 x + 21 = 0

What are the solutions to the equation x+(x*0.1x)=75 ?
The solutions to the equation x+(x*0.1x)=75 are x=(-1+sqrt(31))/(0.2),x=(-1-sqrt(31))/(0.2)
Find the zeros of x+(x*0.1x)=75
The zeros of x+(x*0.1x)=75 are x=(-1+sqrt(31))/(0.2),x=(-1-sqrt(31))/(0.2)