What are the solutions to the equation 2x^2-x=-6 ?

The solutions to the equation 2x^2-x=-6 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

Find the zeros of 2x^2-x=-6

The zeros of 2x^2-x=-6 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

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2 x^{2} - x = - 6

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

Solution steps

2 x^{2} - x = - 6

Move

6

to the left side

2 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 6 : 47 i

x_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 47 i}{2 \cdot 2} : \frac{1}{4} + i \frac{47}{4}

x = \frac{- ( - 1 ) - 47 i}{2 \cdot 2} : \frac{1}{4} - i \frac{47}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

\frac{- 3}{1}

∣ 4 ∣ - 7

q^{2} - 5 q + 6

x = \frac{1}{4} x

11 b + 7 = 40

What are the solutions to the equation 2x^2-x=-6 ?
The solutions to the equation 2x^2-x=-6 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4
Find the zeros of 2x^2-x=-6
The zeros of 2x^2-x=-6 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4