What are the solutions to the equation 4(x-10)^2=36 ?

The solutions to the equation 4(x-10)^2=36 are x=13,x=7

Find the zeros of 4(x-10)^2=36

The zeros of 4(x-10)^2=36 are x=13,x=7

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4 (x - 10)^{2} = 36

x = 13, x = 7

Solution steps

4 (x - 10)^{2} = 36

Divide both sides by

4

(x - 10)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 10 = 9 : x = 13

Solve

x - 10 = - 9 : x = 7

The solutions to the quadratic equation are:

x = 13, x = 7

\frac{81 ( 2 ) ^{5} ( 2 + 4 )}{2 ( 2 ( 2 ) + 4 ) ^{2} ( 2 + 2 ) ^{2}}

y, y x^{2} - 2 x^{3} = 36

5 (\frac{1}{3})^{3}

- 5 > 6 (c - 4) + 7

(2 m - 3 + 7 m^{2}) - (3 - 9 m^{2} - 2 m)

What are the solutions to the equation 4(x-10)^2=36 ?
The solutions to the equation 4(x-10)^2=36 are x=13,x=7
Find the zeros of 4(x-10)^2=36
The zeros of 4(x-10)^2=36 are x=13,x=7