What are the solutions to the equation x^2+14x=-34 ?

The solutions to the equation x^2+14x=-34 are x=-7+sqrt(15),x=-7-sqrt(15)

Find the zeros of x^2+14x=-34

The zeros of x^2+14x=-34 are x=-7+sqrt(15),x=-7-sqrt(15)

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x^{2} + 14 x = - 34

x = - 7 + 15, x = - 7 - 15

Decimal Notation

x = - 3.12701 \dots, x = - 10.87298 \dots

Solution steps

x^{2} + 14 x = - 34

Move

34

to the left side

x^{2} + 14 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 34}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 34 = 215

x_{1, 2} = \frac{- 14 \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 15}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 15}{2 \cdot 1}

x = \frac{- 14 + 2 15}{2 \cdot 1} : - 7 + 15

x = \frac{- 14 - 2 15}{2 \cdot 1} : - 7 - 15

The solutions to the quadratic equation are:

x = - 7 + 15, x = - 7 - 15

- 2 - (- 5)

2 = 2 x - 2

(64 m^{4})^{\frac{3}{2}}

- 6 x + 8 = - 3 x - 10

(x^{- \frac{1}{2}})^{2}

What are the solutions to the equation x^2+14x=-34 ?
The solutions to the equation x^2+14x=-34 are x=-7+sqrt(15),x=-7-sqrt(15)
Find the zeros of x^2+14x=-34
The zeros of x^2+14x=-34 are x=-7+sqrt(15),x=-7-sqrt(15)