What is (3x-1)(x+1)>= x(2x-3)-5 ?

The solution to (3x-1)(x+1)>= x(2x-3)-5 is x =-1

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(3x-1)(x+1)>= x(2x-3)-5

(3 x - 1) (x + 1) \geq x (2 x - 3) - 5

x \leq - 4 or x \geq - 1

Interval Notation

(- \infty, - 4] \cup [- 1, \infty)

Solution steps

(3 x - 1) (x + 1) \geq x (2 x - 3) - 5

Rewrite in standard form

x^{2} + 5 x + 4 \geq 0

Factor

x^{2} + 5 x + 4 : (x + 1) (x + 4)

(x + 1) (x + 4) \geq 0

Identify the intervals

x \leq - 4 or x \geq - 1

15 = c - 6

2 x^{2} - 10 x + 5 = 0

x^{2} - a x - x + a

\frac{x ^{2} - 1}{x ^{2} + 2 x - 3}

\frac{n}{7} - 12 = 5 n + 5

What is (3x-1)(x+1)>= x(2x-3)-5 ?
The solution to (3x-1)(x+1)>= x(2x-3)-5 is x<=-4\lor x>=-1