What are the solutions to the equation 81t^2+2=0 ?

The solutions to the equation 81t^2+2=0 are t=(sqrt(2))/9 i,t=-(sqrt(2))/9 i

Find the zeros of 81t^2+2=0

The zeros of 81t^2+2=0 are t=(sqrt(2))/9 i,t=-(sqrt(2))/9 i

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81 t^{2} + 2 = 0

t = \frac{2}{9} i, t = - \frac{2}{9} i

Solution steps

81 t^{2} + 2 = 0

Move

2

to the right side

81 t^{2} = - 2

Divide both sides by

81

t^{2} = - \frac{2}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - \frac{2}{81}, t = - - \frac{2}{81}

- \frac{2}{81} = \frac{2}{9} i

- - \frac{2}{81} = - \frac{2}{9} i

t = \frac{2}{9} i, t = - \frac{2}{9} i

- 6 x^{2} + 56 x = 0

∣ x - 1 ∣ > 5

6 x^{2} + 7 x = 3

\frac{x}{2} + \frac{x}{3} > 5

12 n^{2} + 7 n^{3}

What are the solutions to the equation 81t^2+2=0 ?
The solutions to the equation 81t^2+2=0 are t=(sqrt(2))/9 i,t=-(sqrt(2))/9 i
Find the zeros of 81t^2+2=0
The zeros of 81t^2+2=0 are t=(sqrt(2))/9 i,t=-(sqrt(2))/9 i