(x+3)× |x-1|=1

解

(x + 3) \cdot ∣ x - 1 ∣ = 1

x = - 1 - 3 or x = 3 - 1 or x = - 1 + 5

十進法表記

x = - 2.73205 \dots, x = 0.73205 \dots, x = 1.23606 \dots

解答ステップ

(x + 3) ∣ x - 1 ∣ = 1

正と負の区間を求める

x < 1, x \geq 1

各区間の不等式を解く

(x = - 1 - 3 or x = 3 - 1) or x = - 1 + 5

x = - 1 - 3 or x = 3 - 1 or x = - 1 + 5