ln(x)=2.32

Lösung

ln (x) = 2.32

x = e^{2.32}

Dezimale

x = 10.17567 \dots

Schritte zur Lösung

ln (x) = 2.32

Wende die log Regel an

x = e^{2.32}

ln (5) + ln (2 x) = 3

- lo g_{10} (x) = 4.1

lo g_{4 x} (x) = \frac{9}{5}

ln (x) + ln (4) = 2

lo g_{x} (25) = \frac{- 1}{2}