log_{2}(4x)=6

Lösung

lo g_{2} (4 x) = 6

x = 16

Schritte zur Lösung

lo g_{2} (4 x) = 6

Wende die log Regel an

4 x = 64

Löse

4 x = 64 : x = 16

x = 16

x^{4} + 5 x^{4} ln (x) = 0

ln (x (x + 3)^{2}) = 3

lo g_{3} (a) = - 5

4 ln (x) - 4 = 0

so l v e f or x, ln (x) = - \frac{1}{2}