3^{2x-1}=4^x

Lösung

3^{2 x - 1} = 4^{x}

x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

Dezimale

x = 1.35475 \dots

Schritte zur Lösung

3^{2 x - 1} = 4^{x}

Wende Exponentenregel an

(2 x - 1) ln (3) = x ln (4)

Löse

(2 x - 1) ln (3) = x ln (4) : x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

x = \frac{ln ( 3 )}{2 ( ln ( 3 ) - ln ( 2 ) )}

4^{x - 2} - 6 = 13

2 \times 4^{x} = 64

5^{x - 1} = 3^{2 x + 1}

201 \cdot 2^{x} = 67

4^{5 x + 1} = 16