2^{6-3x}=8^{x+1}

Lösung

2^{6 - 3 x} = 8^{x + 1}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

2^{6 - 3 x} = 8^{x + 1}

Wende Exponentenregel an

6 - 3 x = 3 (x + 1)

Löse

6 - 3 x = 3 (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

2^{2 x} - 12 (2^{x}) + 35 = 0

1 0^{- 3 x} \cdot 1 0^{x} = \frac{1}{10}

e^{x + 1} = 1 0^{2 x}

e^{2 x + 1} = 11

3^{x} + \frac{1}{3 ^{x + 1}} = \frac{28}{9}