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受欢迎的代数 >

413=9x^2+2x+1

解答

413 = 9 x^{2} + 2 x + 1

解答

x = \frac{- 1 + 3709}{9}, x = - \frac{1 + 3709}{9}

+1

十进制

x = 6.65572 \dots, x = - 6.87795 \dots

求解步骤

413 = 9 x^{2} + 2 x + 1

交换两边

9 x^{2} + 2 x + 1 = 413

将

413

para o lado esquerdo

9 x^{2} + 2 x - 412 = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 9 ( - 412 )}{2 \cdot 9}

2^{2} - 4 \cdot 9 (- 412) = 23709

x_{1, 2} = \frac{- 2 \pm 2 3709}{2 \cdot 9}

将解分隔开

x_{1} = \frac{- 2 + 2 3709}{2 \cdot 9}, x_{2} = \frac{- 2 - 2 3709}{2 \cdot 9}

x = \frac{- 2 + 2 3709}{2 \cdot 9} : \frac{- 1 + 3709}{9}

x = \frac{- 2 - 2 3709}{2 \cdot 9} : - \frac{1 + 3709}{9}

二次方程组的解是:

x = \frac{- 1 + 3709}{9}, x = - \frac{1 + 3709}{9}

作图

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