-16t^2-32t+1395=0

解

- 16 t^{2} - 32 t + 1395 = 0

t = - \frac{4 + 1411}{4}, t = \frac{1411 - 4}{4}

十進法表記

t = - 10.39081 \dots, t = 8.39081 \dots

解答ステップ

- 16 t^{2} - 32 t + 1395 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 ( - 16 ) \cdot 1395}{2 ( - 16 )}

(- 32)^{2} - 4 (- 16) \cdot 1395 = 81411

t_{1, 2} = \frac{- ( - 32 ) \pm 8 1411}{2 ( - 16 )}

解を分離する

t_{1} = \frac{- ( - 32 ) + 8 1411}{2 ( - 16 )}, t_{2} = \frac{- ( - 32 ) - 8 1411}{2 ( - 16 )}

t = \frac{- ( - 32 ) + 8 1411}{2 ( - 16 )} : - \frac{4 + 1411}{4}

t = \frac{- ( - 32 ) - 8 1411}{2 ( - 16 )} : \frac{1411 - 4}{4}

二次equationの解:

t = - \frac{4 + 1411}{4}, t = \frac{1411 - 4}{4}