(x+1)/(x-2)<2

Lösung

\frac{x + 1}{x - 2} < 2

x < 2 or x > 5

Intervall-Notation

(- \infty, 2) \cup (5, \infty)

Schritte zur Lösung

\frac{x + 1}{x - 2} < 2

Rewrite in standard form

\frac{- x + 5}{x - 2} < 0

Identifiziere die Intervalle

x < 2 or x > 5

(x - 5) (x + 4) \geq 0

8 x - 8 = - 40

27 = 9 x

6 y = 42

f a c t or 3 a + 6