3x+(y-x)i=6

解答

3 x + (y - x) i = 6

x = 2, y = 2

求解步骤

3 x + (y - x) i = 6

将

6

改写成标准复数形式:

6 + 0 i

3 x + (y - x) i = 6 + 0 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[3 x = 6 y - x = 0]

[3 x = 6 y - x = 0] : x = 2, y = 2

x = 2, y = 2

4 x_{1} + 5 x_{2} = (1 + i) x_{1}

z^{2} - z - 1 + i = 0

+ i x^{2} = 1 - i, x^{1} = 1

- 2 (a + bi) + i (a - bi) = 7 i - 8

x^{2} + x + 3 i = 0