(u-i)(4+iv)=11+2i

解

(u - i) (4 + i v) = 11 + 2 i

(u = 2, v = 3 u = \frac{3}{4}, v = 8)

解答ステップ

(u - i) (4 + i v) = 11 + 2 i

拡張

(u - i) (4 + i v) : (4 u + v) + i (- 4 + uv)

(4 u + v) + i (- 4 + uv) = 11 + 2 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[4 u + v = 11 - 4 + uv = 2]

[4 u + v = 11 - 4 + uv = 2] : (u = 2, v = 3 u = \frac{3}{4}, v = 8)

(u = 2, v = 3 u = \frac{3}{4}, v = 8)