log_{10}(x+2)=2.19

Lösung

lo g_{10} (x + 2) = 2.19

x = 1 0^{2.19} - 2

Dezimale

x = 152.88166 \dots

Schritte zur Lösung

lo g_{10} (x + 2) = 2.19

Wende die log Regel an

x + 2 = 1 0^{2.19}

Löse

x + 2 = 1 0^{2.19} : x = 1 0^{2.19} - 2

x = 1 0^{2.19} - 2

ln (4 x + 5) = 10

60 = 9.95593 ln (x) + 68.691

a = lo g_{10} (x - 4)

ln (x) = 30

ln (x - 6) + ln (x + 3) = ln (x - 22)