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人気のある代数 >

log_{4}(5x+2)=5x

解

lo g_{4} (5 x + 2) = 5 x

解

x = - \frac{W _{- 1} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

+1

十進法表記

x = 0.14449 \dots, x = - 0.38625 \dots

解答ステップ

lo g_{4} (5 x + 2) = 5 x

f (x) = g (x)

ならば,

a^{f (x)} = a^{g (x)}

4^{l o g_{4} (5 x + 2)} = 4^{5 x}

簡素化

4^{l o g_{4} (5 x + 2)} : 5 x + 2

簡素化

4^{5 x} : 102 4^{x}

5 x + 2 = 102 4^{x}

解く

5 x + 2 = 102 4^{x} : x = - \frac{W _{- 1} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

x = - \frac{W _{- 1} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

解を検算する:

x = - \frac{W _{- 1} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

真

, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

真

解答は

x = - \frac{W _{- 1} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}, x = - \frac{W _{0} ( - \frac{l n ( 2 )}{8} ) + 4 ln ( 2 )}{10 ln ( 2 )}

グラフ

人気の例

-log_{10}(x)=7.4

- lo g_{10} (x) = 7.4

-log_{10}(x)=7.1

- lo g_{10} (x) = 7.1

x(log_{10}(x)+1)^2=0

x (lo g_{10} (x) + 1)^{2} = 0

7.3=log_{10}(H)

7.3 = lo g_{10} (H)

ln(4x)+ln(3)=ln(7x+7)

ln (4 x) + ln (3) = ln (7 x + 7)