ln(x+1)=pi

Lösung

ln (x + 1) = π

x = e^{π} - 1

Dezimale

x = 22.14069 \dots

Schritte zur Lösung

ln (x + 1) = π

Wende die log Regel an

x + 1 = e^{π}

Löse

x + 1 = e^{π} : x = e^{π} - 1

x = e^{π} - 1

lo g_{10} (x) = - 0.3

lo g_{10} (x) = - 0.2

lo g_{10} (x) = - 0.5

- 1 - 5 \cdot ln (x) = 0.7

lo g_{10} (X) = 0.9469