ln(1-x)=2

Lösung

ln (1 - x) = 2

x = - e^{2} + 1

Dezimale

x = - 6.38905 \dots

Schritte zur Lösung

ln (1 - x) = 2

Wende die log Regel an

1 - x = e^{2}

Löse

1 - x = e^{2} : x = - e^{2} + 1

x = - e^{2} + 1

ln (x - 3) = - 1

121 = lo g_{10} (2 x + 1)

lo g_{77} (lo g_{7} (x)) = 0

lo g_{x} (1) = x

lo g_{10} (\frac{1}{x}) = 2.04