solvefor x,ln(x^2)=20

解答

求解

x, ln (x^{2}) = 20

x = e^{10}, x = - e^{10}

十进制

x = 22026.46579 \dots, x = - 22026.46579 \dots

求解步骤

ln (x^{2}) = 20

使用对数运算法则

x^{2} = e^{20}

解

x^{2} = e^{20} : x = e^{10}, x = - e^{10}

x = e^{10}, x = - e^{10}

lo g_{9} (x) = \frac{- 3}{2}

lo g_{5 - x} (x^{2} - 2 x + 65) = 2

so l v e f or x, ln (x^{3} y^{3}) = c

so l v e f or x, ln (x^{3} y^{3}) = 1

\frac{24}{x ( 4 ln ( x ) + 3 ) ^{2}} = 0