log_{2}(5x+5)=5

Lösung

lo g_{2} (5 x + 5) = 5

x = \frac{27}{5}

Dezimale

x = 5.4

Schritte zur Lösung

lo g_{2} (5 x + 5) = 5

Wende die log Regel an

5 x + 5 = 32

Löse

5 x + 5 = 32 : x = \frac{27}{5}

x = \frac{27}{5}

lo g_{2} (x + 1) = 0

lo g_{d} (5) = \frac{1}{2}

ln (2 x + 5) - ln (x) = 4

1 - lo g_{2} (1 - x^{2}) = 2

4 + ln (27 x) = 22 - 2 ln (x)