log_{4}(3x+1)=3

Lösung

lo g_{4} (3 x + 1) = 3

x = 21

Schritte zur Lösung

lo g_{4} (3 x + 1) = 3

Wende die log Regel an

3 x + 1 = 64

Löse

3 x + 1 = 64 : x = 21

x = 21

6 - 2 ln (x) = 7

lo g_{4} (\frac{x - 2}{2 x + 3}) = 0

lo g_{10} (x) + lo g_{10} (80) = 3

ln (x^{- 1}) = 3

so l v e f or x, ln (x) + ln (x) = 0