log_{3}(x-1)=-1

Lösung

lo g_{3} (x - 1) = - 1

x = \frac{4}{3}

Dezimale

x = 1.33333 \dots

Schritte zur Lösung

lo g_{3} (x - 1) = - 1

Wende die log Regel an

x - 1 = \frac{1}{3}

Löse

x - 1 = \frac{1}{3} : x = \frac{4}{3}

x = \frac{4}{3}

ln (x) - ln (2) = 0

2^{4} = 16 lo g_{2} (x)

lo g_{2} (4 x - 12) = 5

ln (6 x) + ln (4) = ln (6 x + 7)

lo g_{3 x} (9 x + 10) = 2