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人気のある代数 >

x=-2log_{2}(x)

解

x = - 2 lo g_{2} (x)

解

x = \frac{2 W _{0} ( \frac{l n ( 2 )}{2} )}{ln ( 2 )}

+1

十進法表記

x = 0.76666 \dots

解答ステップ

x = - 2 lo g_{2} (x)

辺を交換する

- 2 lo g_{2} (x) = x

以下で両辺を割る

- 2

lo g_{2} (x) = - \frac{x}{2}

f (x) = g (x)

ならば,

a^{f (x)} = a^{g (x)}

2^{l o g_{2} (x)} = 2^{- \frac{x}{2}}

簡素化

2^{l o g_{2} (x)} : x

x = 2^{- \frac{x}{2}}

解く

x = 2^{- \frac{x}{2}} : x = \frac{2 W _{0} ( \frac{l n ( 2 )}{2} )}{ln ( 2 )}

x = \frac{2 W _{0} ( \frac{l n ( 2 )}{2} )}{ln ( 2 )}

解を検算する:

x = \frac{2 W _{0} ( \frac{l n ( 2 )}{2} )}{ln ( 2 )}

真

解は

x = \frac{2 W _{0} ( \frac{l n ( 2 )}{2} )}{ln ( 2 )}

グラフ

人気の例

solvefor x,y=-log_{10}(x)

so l v e f or x, y = - lo g_{10} (x)

log_{10}(x-2/4)=2

lo g_{10} (x - \frac{2}{4}) = 2

log_{2}(x-1)=2log_{2}(x+1)

lo g_{2} (x - 1) = 2 lo g_{2} (x + 1)

log_{5}(x)=1+log_{x}(25)

lo g_{5} (x) = 1 + lo g_{x} (25)

log_{x}(8x-15)=2

lo g_{x} (8 x - 15) = 2