solvefor x,y=ln(x+1)

Lösung

löse nach

x, y = ln (x + 1)

x = e^{y} - 1

Schritte zur Lösung

y = ln (x + 1)

Wende die log Regel an

e^{y} = x + 1

Löse

e^{y} = x + 1 : x = e^{y} - 1

x = e^{y} - 1

lo g_{10} (x + 1) = 1

lo g_{3} (x) = - 2

ln (D (t)) = ln (50) + t ln (0.9)

0.55 = lo g_{10} (x)

0.64 = ln (x)